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pH and Buffers
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Buffers and pH
| Strong acids | Weak acids | Application in the cell |

An understanding of what H ion concentration means and how H ion concentration changes is very important in biochemical processes and in following clinical progression of certain disease processes. The concentrations are usually expressed as one mole/liter (1M or gram molecular weight of a compound in 1000 gm of solvent; in case of water 1000 gm=1000 ml or one liter) of water); one mmole/liter (1 mM); one mmole/liter (1mM) and so on. In Biochemistry, concentrations are always expressed in this way.

Strong Acids
   If you put 1 mmole of HCl in a liter of water its concentration would be 1 mM. Since HCl is a strong acid, it is completely dissociated in water:

HCl -----> H+  +  Cl-.    

   Note that H+ (also called a proton) and Cl- ions (called anions or conjugate base) are surrounded by water molecules and form hydrogen bonds with a number of water molecules. Because of this essentially irreversible dissociation, the concentrations of protons and Cl- ions would be equal to 1 mM. The hydrogen ion concentration is therefore, 1 mM or 10-3 M.
   This way of representation H+ is cumbersome and has been changed to a logarithmic scale called pH:

pH= - log {H+} where {H+} is represented in gram equivalent per liter. --- (eq.1)

   Since 1 mM HCl provides 1 mequivalent of H+ and one mequivalent of Cl ions, the pH of 1mM HCl would be:

pH= -log {10-3m Equ/lt} = - (-) log {103} = 3 log10 =3.

   Thus pH values can be expressed as whole numbers and fractions. For "strong' acids like H2SO4 complete dissociation in water would yield two equivalents of H+ and one equivalent of SO4 ions. Therefore, 1 mM H2SO4 would provide 2 m equivalents of H+ and one equivalent of SO4 ions. The pH of 1 mM H2SO4 solution would be:

pH = - log {2x10-3 m equ} =2.7

   For acids which do not completely dissociate into H ions and anions, one would have to calculate their H+ concentrations from their known dissociation constants (Ka). The section on Ka will be discussed later.

Weak Acids
   Weak acids will dissociate in solution, but they do so less than 100%. So water dissociates to H+ and OH- ions to a very small extent. This can be represented as:

H2O  <------------>  H+  + OH-.

   This is represented by a dissociation constant, Ka.
   Therefore

Ka = {H}{OH}/H2O. -------------(eq. 2)

   The concentration of water is very high ( 55.5 M; 1000/18 gm mol weight of water) compared to H or OH concentrations. Therefore both sides of equation are multiplied by 55.5 M to give a new expression:

Ka x 55.5M = Kw = {H}{OH}. The value of Kw = 10 -14 M2 ---------(eq. 3)

   Since in water the concentrations of H and OH ions are equal, one can write:

{H+}{OH} = {H+}2 = 10-14 M2 or {H+} = 10--7 M
Therefore pH of water would be - log {10-7M} = 7.

   A pH of 7 is called neutral because the concentration of H and OH ions are equal, so the solution is neither acidic or alkaline.
   Equation 3 also indicates that:

pH + pOH =14; thus if pH=7 then pOH =7.

   When a solution becomes more acidic i.e. if pH is 6, the the pOH would be 14-6 =8. This means that when {H+} is 10-6M, the {OH} is 10-8M.
   Weak acids like acetic acid, lactic acid do not completely dissociate into {H+} and conjugate base. Therefore, the concentration of {H+} would have to be calculated knowing the total concentrations of acid and conjugate base.

Application in the Cell

Amino acids, like other organic molecules, can be characterized in terms of their chemical and physical properties.  One of the most important of these is their ability to undergo proton dissociation or association.  The amino group of an amino acid is a (moderately) weak base.  The carboxyl group is a weak acid.

  The extent to which a carboxyl group of a specific amino acid undergoes proton dissociation is expressed by an acid-dissociation constant, Ka, which describes the following process occurring, from left to right:

 AH  +  H2O   =====   H3O+     +     A-

             [H3O+] [A-]
 Ka  =    --------------------
             [AH] [H2O]
 

 and, pH = pKa + log  [A-]/[HA]    ......... Henderson-Hasselbach equation

The dissociation of a proton from the protonated form of the amino group of an amino acid can also be described in terms of Ka, as follows:

 RNH3+  +  H2O  =====  RNH2  +  H3O+

           [RNH2] [ H3O+]
 Ka   = ------------------
           [RNH3+] [H2O]

In order to avoid the use of exponents, the extent of proton dissociation can be expressed in terms of pKa.  Just as pH is the negative logarithm of hydrogen ion concentration, pKa is the negative logarithm of the acid dissociation constant.

The following are useful in calculations relating to buffering:

ml x N   =  milliequivalents,  or
liters x N   =  equivalents, and
pH =  pKa  +  log ([conjugate base] / [conjugate acid])

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